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CCSS Math Answers

Eureka Math Grade 5 Module 2 Lesson 3 Answer Key

Engage ny eureka math 5th grade module 2 lesson 3 answer key, eureka math grade 5 module 2 lesson 3 problem set answer key.

Question 1. Draw a model. Then, write the numerical expressions. a. The sum of 8 and 7, doubled

Answer: The sum of 8 and 7, doubled = 30.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-1

b. 4 times the sum of 14 and 26

Answer: The sum of 14 and 26, 4 times = 160.

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c. 3 times the difference between 37.5 and 24.5

Answer: The difference of 37.5 and 24.5, 3 times = 13.0.

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d. The sum of 3 sixteens and 2 nines

Answer: The sum of 3 sixteens and 2 nines = 30.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-4

e. The difference between 4 twenty-fives and 3 twenty-fives

Answer: The difference between 4 25 and 3 25 = 25.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-5

f. Triple the sum of 33 and 27

Answer: The sum of 33 and 27, 3 times = 180.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-6

Question 2. Write the numerical expressions in words. Then, solve.

Answer: 360.

Explanation: In the above-given question, given that, 12 x ( 5 + 25). 12 x (30). 360.

Answer: 550.

Explanation: In the above-given question, given that, (62 – 12) × 11 50 x 11 = 550.

Answer: 2300.

Explanation: In the above-given question, given that, (45 + 55) × 23. 100 x 23. 2300.

Answer: 76.

Explanation: In the above-given question, given that, (30 × 2) + (8 × 2) 60 + 16. 76.

Eureka Math Grade 5 Module 2 Lesson 3 Problem Set Answer Key 1

Answer: 600 > 360.

Explanation: In the above-given question, given that, 24 x (20 + 5). 24 x 25. 600. (20 + 5) x 12. 30 x 12. 360. 600 > 360.

Answer: 487 > 513.

Explanation: In the above-given question, given that, 18 x 27. 487. 20 twenty-seven – 1 27. 540 – 27. 513. 487 < 513.

Answer: 171 = 171.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-7

Question 4. Mr. Huynh wrote the sum of 7 fifteens and 38 fifteens on the board. Draw a model, and write the correct expression.

Answer: The sum of 7 fifteens and 38 fifteens = 675.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-8

Question 5. Two students wrote the following numerical expressions. Angeline: (7 + 15) × (38 + 15) MeiLing: 15 × (7 + 38)   Are the students’ expressions equivalent to your answer in Problem 4? Explain your answer.

Answer: Yes, the student’s expressions equivalent.

Explanation: In the above-given question, given that, Angeline: (7 + 15) × (38 + 15) Meiling: 15 × (7 + 38)   105 + 570 = 675.

Question 6. A box contains 24 oranges. Mr. Lee ordered 8 boxes for his store and 12 boxes for his restaurant. a. Write an expression to show how to find the total number of oranges ordered.

Answer: The total number of oranges ordered= 480.

Explanation: In the above-given question, given that, A box contains 24 oranges. Mr. Lee ordered 8 boxes for his store and 12 boxes for his restaurant. ( 24 x 8 ) + ( 24 x 12) 192 + 288 480

b. Next week, Mr. Lee will double the number of boxes he orders. Write a new expression to represent the number of oranges in next week’s order.

Answer: The total number of oranges ordered= 960.

Explanation: In the above-given question, given that, A box contains 24 oranges. Mr. Lee ordered 8 boxes for his store and 12 boxes for his restaurant. ( 24 x 8 ) + ( 24 x 12) 192 + 288 480 + 480 = 960

c. Evaluate your expression from Part (b) to find the total number of oranges ordered in both weeks.

Answer: The total number of oranges ordered in both weeks = 1440.

Explanation: In the above-given question, given that, 960 + 480 = 1440.

Eureka Math Grade 5 Module 2 Lesson 3 Exit Ticket Answer Key

Question 1. Draw a model. Then, write the numerical expressions. a. The difference between 8 forty-sevens and 7 forty-sevens

Answer: The difference of 8 forty-sevens and 7 forty-sevens = 47.

Explanation: In the above-given question, given that, the difference of 8 forty sevens and 7 forty-sevens. 8 x 47 – 7 x 47. 376 – 329. 47

b. 6 times the sum of 12 and 8

Answer: The sum of 12 and 8, 6 times = 120.

Explanation: In the above-given question, given that, the sum of 12 and 8 is 120. 20 + 20 + 20 + 20 + 20 + 20 = 120. 12 + 8 = 20.

Eureka Math Grade 5 Module 2 Lesson 3 Exit Ticket Answer Key 2

Answer: 4836 > 2028.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-9

Eureka Math Grade 5 Module 2 Lesson 3 Homework Answer Key

Question 1. Draw a model. Then, write the numerical expressions. a. The sum of 21 and 4, doubled b. 5 times the sum of 7 and 23 c. 2 times the difference between 49.5 and 37.5 d. The sum of 3 fifteens and 4 twos e. The difference between 9 thirty-sevens and 8 thirty-sevens f. Triple the sum of 45 and 55

Answer: The sum of 21 and 4, 2 times = 50.

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Answer: The sum of 7 and 23, 5 times = 150.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-11

Answer: 2 times the difference between 49.5 and 37.5 = 24.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-12

Answer: The sum of 3 fifteens and 4 twos = 53.

Eureka-Math-Grade-5-Module-2-Lesson-3-Answer Key-13

Answer: The difference between 9 thirty-sevens and 8 thirty-sevens = 37.

Explanation: In the above-given question, given that, The difference between 9 thirty-sevens and 8 thirty-sevens 9 x 37 – 8 x 37. 333 – 296. 37.

Triple the sum of 45 and 55 = 300.

Explanation: In the above-given question, given that, Triple the sum of 45 and 55 45 + 55 = 100. 100 + 100 + 100 = 300.

Answer: 160.

Explanation: In the above-given question, given that, 10 x ( 2.5 + 13.5). 10 x (16). 160.

Answer: 220.

Explanation: In the above-given question, given that, 11 x ( 98 – 78). 11 x (20). 220.

Answer: 2600.

Explanation: In the above-given question, given that, 26 x ( 71 + 29). 26 x (30). 2600.

Answer: 3000.

Explanation: In the above-given question, given that, (50 x 2) + ( 15 + 2). 100 x (30). 3000.

Eureka Math Grade 5 Module 2 Lesson 3 Homework Answer Key 11

Answer: 3906 > 1438.

Explanation: In the above-given question, given that, 93 x ( 40 + 2). 93 x (42). 3906. (40 + 2) x 36 42 x 36. 1438. 3906 > 1438.

Answer: 1525 > 1475.

Explanation: In the above-given question, given that, 61 x ( 25). 1525. 60 twenty fives minus one twenty-five. 60  x 25 – 25. 1500 – 25. 1475. 1525 > 1475.

Question 4. Larry claims that (14 + 12) × (8 + 12) and (14 × 12) + (8 × 12) are equivalent because they have the same digits and the same operations. a. Is Larry correct? Explain your thinking.

Answer: Yes, Larry was not correct.

Explanation: In the above-given question, given that, Larry claims that (14 + 12) x (8 + 12) and (14 x 12) + (8 x 12). 42 + 12 = 26. 8 + 12 = 20. 26 x 20 = 520. (14 x 12) + (8 x 12). 168 + 96. 264. 520 is not equal to 264.

b. Which expression is greater? How much greater?

Answer: (14 + 12) x (8 + 12) is greater. 256 is greater.

Explanation: In the above-given question, given that, 42 + 12 = 26. 8 + 12 = 20. 26 x 20 = 520. (14 x 12) + (8 x 12). 168 + 96. 264. 520 is not equal to 264.

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  4. Eureka Math Grade 5 Module 2 Lesson 3 Answer Key

    eureka math grade 5 module 2 lesson 3 homework

  5. EUREKA MATH LESSON 2 HOMEWORK 5.3

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  6. Engage NY // Eureka Math Grade 5 Module 3 Lesson 2 Homework

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