lab charles law assignment quizlet

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Lab 11 Assignment Report

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Lab 11 charles’ law.

Title: Charles’s Law

Introduction: Charles law states that constant pressure, the volume of a particular sample of gas is directly related to the temperature. An Increase in temperature will cause the molecules of a gas to move faster and exert more pressure or cause the gas to expand. Volume of air at high temperature will decrease when a sample is cooled to a lower temperature.

Pre-laboratory Questions: The purpose of the lab is to verify the relationship between volume and temperature by observing and measuring the volume of air at a high temperature and low temperature. The volume measured at the low temperature will be compared to the theoretical predicted by Charles law.

Pre - Lab Answer the following.

The quantitative relationship between the volume and the absolute temperature of a gas is summarized in Charles __ Law.

The temperature in Charles’ Law is in Kelvin

Report Data: A boiling bath of 200 mL water was prepared using a 400 mL beaker. A Rubber stopper was inserted into a clean and dry 125 mL beaker. The 125 mL beaker was then submerged into the boiling water for 10 minutes. A cold-water bath was prepared. The Flask was removed from the boiling water a submerged into a cold-water bath after securing and clamping rubber tubing to the top. The flask was submerged with the rubber tubing facing down in the water. The flask was left to sit in the cold-water bath for another 10 minutes. The temperature of the cold-water bath was measured and recorded. The temperature of the boiling water was also measured and recorded. After 10 minutes the flask was removed from the cold-water bath and the volume of the water that entered the flask was recorded. The flask was filled to the bottom of the rubber stopper and the water was poured into a graduated cylinder the volume of the water was measured and recorded.

The pressure of dry air was calculated by subtracting the volume of wet air from the vapor pressure of water. The experimental volume of dry air was calculated by dividing the pressure of dry air by the temperature of the boiling water in kelvin and multiplying by the volume of water collected after cooling. The theoretical volume of air was calculated by dividing the temperature of the cold water in kelvin by the temperature of the hot water in kelvin and multiplying by the volume of water collected after cooling. The percent error was determined by subtracting the theoretical volume of air by the experimental volume of air, dividing the sum by the theoretical volume of air and multiplying by 100. The theoretical V/T ration was calculated by dividing the volume of air at high temperature by the temperature of the hot water in kelvin. The experimental V/T ratio was determined by dividing the theoretical volume of air by the temperature of the cold water bath.

Experiments: Temperature of boiling water, TH 99 C 373 K Temperature of cold water, TL 23 C 296 K Volume of water collected after cooling 18 mL Volume of air at high temperature (VH) 148 mL Volume of wet air at TL (PATM) 736 Torr Vapor pressure of water at TL (PH2O) 12 Torr

Pressure of dry air PDA = PATM – PH2O 736 – 12.

Corrected experimental volume of dry air at TL VDA= (VEXP)(PDA/PATM) 18 (724 /736)

Theoretical volume of air at TL (VL) VL=VH (TL/TH) 148 (296.65/373)

Percent error VL-VDA/VL (100) 117 -17.704/117 (100)

Theoretical V/T ratio VH/TH 148/373.

Experimental V/T ratio VDA/TL 117/296.

Post Laboratory Questions: 1. What is the reason for equalizing the water levels inside and outside the flask before removing the flask from the cold water?